User talk:Dominic3203

Citation bot

Why did you run the citation bot through all of the draft pages in my userspace? I do find that a little odd to do that without asking me. The C of E God Save the King! (talk) 19:07, 9 October 2024 (UTC)

There is currently a discussion at Wikipedia:Administrators' noticeboard/Incidents regarding an issue with which you may have been involved. Thank you. The C of E God Save the King! (talk) 15:50, 11 October 2024 (UTC)

The discussion is still open, please would you be able to come to ANI and discuss why you did this? The C of E God Save the King! (talk) 09:16, 18 October 2024 (UTC)

@Dominic3203: There are two choices: stop editing pages in other editor's userspace, or join the ANI discussion and justify your plans. Johnuniq (talk) 09:21, 18 October 2024 (UTC)

Advice

Hello, Dominic3203,

I see you have returned to editing but you haven't come by ANI to address concerns about your editing. Please do so the next time you log on to the project or you risk losing your editing privileges. Thank you. Liz ^{Read! Talk!} 02:04, 22 October 2024 (UTC)

Disambiguation link notification for November 9

An automated process has detected that when you recently edited Progress trap, you added a link pointing to the disambiguation page Instrument.

(Opt-out instructions.) --DPL bot (talk) 19:56, 9 November 2024 (UTC)

I see that you have not corrected the mistake you were told about in the message above, despite having made several other edits since it was posted here. It is best to avoid making that mistake, by checking that any link you are thinking of posting links to an appropriate target before deciding to add it; if, however you do add a disambiguation link to an article and you are told you have done so, please go back and correct it.

I also noticed that in the same edit you did a number of examples of what is known as "overlinking". Wikilinks can be very helpful, but it is a mistake to add too many wikilinks to articles. Generally speaking, a wikilink should be added only if it provides information which is likely to help readers of the article in which the link is placed to understand content of that article, or provide further information closely connected to the subject of that article. That normally means either a link to an article which explains words or expressions in the article containing the link, or a link to an article which provides background information which is necessary in order to understand content of the article containing the link. Linking to articles in other situations is not just unnecessary, it can actually be harmful, because research has established that the more irrelevant, or only slightly relevant, links there are in a page, the less likely readers are to find the ones which they might find useful. Thus, for example, nobody reading the article Progress trap is likely to need to consult the article Instrument in order to understand the content of Progress trap, so linking to Instrument is not likely to be helpful.

On this occasion I have reverted your edit, but it will help if you can bear these points in mind. JBW (talk) 11:15, 13 November 2024 (UTC)

Since posting the message above, I have seen that you have previously received a number of disambiguation link notifications, which you have deleted. Please don't ignore disambiguation link notifications. JBW (talk) 11:19, 13 November 2024 (UTC)

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Your submission at Articles for creation: Sleepsort (November 20)

Your recent article submission to Articles for Creation has been reviewed. Unfortunately, it has not been accepted at this time. The reason left by 1AmNobody24 was: Please check the submission for any additional comments left by the reviewer. You are encouraged to edit the submission to address the issues raised and resubmit after they have been resolved.

• If you would like to continue working on the submission, go to Draft:Sleepsort and click on the "Edit" tab at the top of the window.
• If you do not edit your draft in the next 6 months, it will be considered abandoned and may be deleted.
• If you need any assistance, or have experienced any untoward behavior associated with this submission, you can ask for help at the Articles for creation help desk, on the reviewer's talk page or use Wikipedia's real-time chat help from experienced editors.

Nobody (talk) 13:59, 20 November 2024 (UTC)

Hello, Dominic3203! Having an article draft declined at Articles for Creation can be disappointing. If you are wondering why your article submission was declined, please post a question at the Articles for creation help desk. If you have any other questions about your editing experience, we'd love to help you at the Teahouse, a friendly space on Wikipedia where experienced editors lend a hand to help new editors like yourself! See you there! Nobody (talk) 13:59, 20 November 2024 (UTC)

Your submission at Articles for creation: Sleep sort (November 20)

Your recent article submission to Articles for Creation has been reviewed. Unfortunately, it has not been accepted at this time. The reasons left by 1AmNobody24 were: Please check the submission for any additional comments left by the reviewer. You are encouraged to edit the submission to address the issues raised and resubmit after they have been resolved.

• If you would like to continue working on the submission, go to Draft:Sleep sort and click on the "Edit" tab at the top of the window.
• If you do not edit your draft in the next 6 months, it will be considered abandoned and may be deleted.
• If you need any assistance, or have experienced any untoward behavior associated with this submission, you can ask for help at the Articles for creation help desk, on the reviewer's talk page or use Wikipedia's real-time chat help from experienced editors.

Nobody (talk) 14:00, 20 November 2024 (UTC)

roots of adjacent squares mod p*q(large)

Hi there, Thanks for your recent edit of my personal page(math blog).

For your interest if you consider the residue to be a complex number and apply the inverse of the complex number equation, you can get the roots of adjacent squares instantly no matter how big the modulus is. (You get adjacent squares, you can't pick the adjacent squares, note)

a is the difference of the roots o is the difference of the squares try222a[a_, pq1_, o_] :=

Module[{a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, pq}, pq = pq1;
 a1 = Mod[PowerMod[a, -1, pq] PowerMod[-o, 1, pq], pq];
 a2 = Mod[(a + a1) PowerMod[2, -1, pq], pq];
 a3 = Mod[-(a - a2) , pq];
 Print[{{a2, a3}, {Mod[a2^2, pq], Mod[a3^2, pq]}}];
 root1 = a2;
 root2 = a3;
 square1 = Mod[a2^2, pq];
 square2 = Mod[a3^2, pq];]

aa is sum of the roots o is difference of the squares

try222b[aa_, p_, q_, o_] :=

Module[{a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, pq},
 pq = p q;
 a1 = PowerMod[aa, -1, pq];
 a2 = Mod[o^2 a1 + o aa, pq];
 a3 = Mod[a2 PowerMod[2 o, -1, pq], pq];
 a4 = Mod[aa - a3, pq];
 Print[{{a3, a4}, {Mod[a3^2, pq], Mod[a4^2, pq]}}];
      ]

calling this routine we get squares 2 apart

try222b[1011, 41, 73, 2]

{{1179,2825},{1289,1287}}

now we get squares 6 apart

try222b[1011, 41, 73, 6]

Endo999 (talk) 00:44, 25 November 2024 (UTC)

p and q parameters can be changed to pq quite easily Endo999 (talk) 00:44, 25 November 2024 (UTC)

@Endo999 Greetings, I wasn't aware of the content while editing the TeX. However, you mentioned something similar to my current project (I posted online), and I'd like to explore this further. Specifically, I'm interested in finding huge triangular numbers and using it to compute large multiplication, by the identity Failed to parse (syntax error): {\displaystyle a × b = T ( a + b ) - ( T ( a ) + T ( b ) ) } , $T(n)$ is the nth triangular number. Could you please provide more details about the connection? This could potentially save considerable time and effort. Dominic3203 (talk) 01:37, 25 November 2024 (UTC)

I have my own Math blog too 😄

https://quora.com/Dominic-Shum Dominic3203 (talk) 01:39, 25 November 2024 (UTC)

I don't know much about trianglar numbers, but this process can be used in modular arithmetic when you know 1) the sum or subtraction of the roots and 2) the subtraction of the squares.

the actual complex inverse equation in modular arithmetic is:

(x+(y/i)*i)^(-1) mod p*q=== (x-y)/(x^2+(1/(-1))y^2) mod p*q

now if you then know the denominator (the difference of the squares) then you have

(x+y) and (x-y)

from these two numbers you can determine x and y

Good luck with your numeric task. Let me know if you suceed.

Endo999 (talk) 03:49, 25 November 2024 (UTC)