User:Gesalbte

This user can contribute with a near-native level of English.

該用戶能以熟練的中文進行交流。
该用户能以熟练的中文进行交流。

Dieser Benutzer hat fortgeschrittene Deutschkenntnisse.

Hic usor simplici latinitate contribuere potest.

この利用者は初級の日本語ができます。

ipa-3
ə

This user has an advanced understanding of the International Phonetic Alphabet.

This user thinks good grammar is sexy.

US

This user uses American English.

~~big words~~

This user opposes the use of ~~esoteric, abstruse and recondite~~ ^big words in Wikipedia articles when simple ones will do.

to¦go

This user chooses to sometimes use split infinitives.

by

This user does not use the passive voice.

Thou/Ye

This user wants to resurrect the T–V distinction in English.

This user lives in the
United States of America.

DL	This user supports the Left Party of Germany

This user loves Science.

This user is interested in the belief that the Meaning of life is to Improve Oneself.

This user is a professional chemist.

Commerce

This user is a student of Commerce (Business and Economics).

TV-0

This user has no television set.

This user enjoys ballet dancing.

This user is already a citizen of Heaven because he believes Jesus is the only way.

This user is a student of Economics.

Q

This user is a rationalist.

This user has a keen interest in physics.

This user is interested in the Byzantine Empire.

This user has been assimilated. Resistance is futile.

This user is interested in the Crusades.

This user enjoys classical music (especially with Violin).

Calculus

\int _{a}^{b}f(x)\,dx=F(b)-F(a).

{\begin{aligned}\lim _{m\rightarrow +\infty }P(1+{\frac {r}{m}})^{mt}&=\lim _{m\rightarrow +\infty }P{\frac {{[(m+r)^{mt}]}'}{{(m^{mt})}'}}\\&=\lim _{m\rightarrow +\infty }P{\dfrac {{\dfrac {\operatorname {d} [(m+r)^{m}]^{t}}{\operatorname {d} [(m+r)^{m}]}}\centerdot {\dfrac {\operatorname {d} [(m+r)^{m}]}{\operatorname {d} (m+r)}}\centerdot {\dfrac {\operatorname {d} (m+r)}{\operatorname {d} m}}}{{\dfrac {\operatorname {d} (m^{m})^{t}}{\operatorname {d} (m^{m})}}\centerdot {\dfrac {\operatorname {d} m^{m}}{\operatorname {d} m}}}}\\&=\lim _{m\rightarrow +\infty }P{\frac {t(m+r)^{(t-1)m}\centerdot (m+r)^{m}[1+\ln {(m+r)}]\centerdot (1+r)}{t[m^{(t-1)m}]\centerdot m^{m}(1+\ln m)}}\\&=\lim _{m\rightarrow +\infty }P(1+r)\\&=P(1+r)\end{aligned}}