1864 United States presidential election in Tennessee
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Elections in Tennessee |
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The 1864 United States presidential election in Tennessee took place on November 8, 1864, as part of the 1864 United States presidential election. The state legislature chose 10 electors to the Electoral College, who voted for president and vice president.
Tennessee voted for the National Union candidate, incumbent Republican President Abraham Lincoln. The state (along with Louisiana) chose electors for the election after being captured early in the American Civil War. However, due to issues related to the Civil War, their votes were rejected.
The Chicago Tribune reported that about 30,000 votes were cast for Lincoln and 5,000 for Democratic candidate George B. McClellan, but that many ballot boxes were destroyed by Confederate guerrillas and thus the exact number was not known.[2] In marked contrast, Anne H. Hopkins and William Lyons claim Lincoln won 99.2% of 17,264 votes cast in Tennessee, without specifying the exact number of votes for either ticket.[3]
If these figures are taken to be correct or even remotely close to correct, then Lincoln's share of the total vote is the best Republican performance ever in Tennessee for a presidential election.
Footnotes
[edit]References
[edit]- ^ Donald, David Herbert; Baker, Jean Harvey; Holt, Michael F. (2001). The Civil War and Reconstruction. New York: W. W. Norton & Company. p. 427. ISBN 9780393974270.
- ^ Humanities, National Endowment for the (November 18, 1864). "Chicago tribune. [volume] (Chicago, Ill.) 1864-1872, November 18, 1864, Image 2". ISSN 2572-9977. Retrieved December 5, 2021.
- ^ Hopkins, Anne H.; Lyons, William (1978). Tennessee Votes, 1799-1976. Knoxville: University of Tennessee. p. 46.