Douglas Township, Saunders County, Nebraska
Appearance
Douglas Township | |
---|---|
![]() Location in Saunders County | |
Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W | |
Country | United States |
State | Nebraska |
County | Saunders |
Area | |
• Total | 32.01 sq mi (82.91 km2) |
• Land | 32.01 sq mi (82.91 km2) |
• Water | 0 sq mi (0 km2) 0% |
Elevation | 1,309 ft (399 m) |
Population | |
• Total | 211 |
• Density | 6.6/sq mi (2.5/km2) |
GNIS feature ID | 0837967 |
Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 211 at the 2020 census. A 2021 estimate placed the township's population at 215.[1]
See also
[edit]References
[edit]- ^ a b Bureau, US Census. "City and Town Population Totals: 2020-2021". Census.gov. US Census Bureau. Retrieved January 25, 2023.
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External links
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