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Douglas Township, Saunders County, Nebraska

Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694
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Douglas Township
Location in Saunders County
Location in Saunders County
Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694
CountryUnited States
StateNebraska
CountySaunders
Area
 • Total32.01 sq mi (82.91 km2)
 • Land32.01 sq mi (82.91 km2)
 • Water0 sq mi (0 km2)  0%
Elevation
1,309 ft (399 m)
Population
 • Total211
 • Density6.6/sq mi (2.5/km2)
GNIS feature ID0837967

Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 211 at the 2020 census. A 2021 estimate placed the township's population at 215.[1]

See also

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References

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  1. ^ a b Bureau, US Census. "City and Town Population Totals: 2020-2021". Census.gov. US Census Bureau. Retrieved January 25, 2023. {{cite web}}: |last1= has generic name (help)
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