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1792 United States presidential election in Vermont

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1792 United States presidential election in Vermont

November 2 - December 5, 1792 1796 →
 
Nominee George Washington John Adams
Party Independent Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Vermont took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose four members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for president.

Vermont participated in its first ever presidential election, having become the 14th state on March 4, 1791. The state cast three electoral votes for incumbent George Washington and three for the incumbent vice president John Adams;[1][2] one elector did not cast his votes.[3]

See also

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References

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  1. ^ Coolidge, Austin Jacobs; Mansfield, John Brainard (1859). A History and Description of New England, General and Local: Maine, New Hampshire, and Vermont. A.J. Coolidge. p. 990.
  2. ^ State, Vermont Office of Secretary of (1886). Vermont Legislative Directory. Rand, Avery. p. 72.
  3. ^ Michigan Official Directory and Legislative Manual for the Years. State of Michigan. 1905. p. 429.