Jump to content

1946 New Hampshire gubernatorial election

From Wikipedia, the free encyclopedia

1946 New Hampshire gubernatorial election

← 1944 November 5, 1946 1948 →
 
Nominee Charles M. Dale F. Clyde Keefe
Party Republican Democratic
Popular vote 103,204 60,247
Percentage 63.14% 36.86%

County results
Dale:      50-60%      60-70%      70-80%      80–90%

Governor before election

Charles M. Dale
Republican

Elected Governor

Charles M. Dale
Republican

The 1946 New Hampshire gubernatorial election was held on November 5, 1946. Incumbent Republican Charles M. Dale defeated Democratic nominee F. Clyde Keefe with 63.14% of the vote.

Primary elections

[edit]

Primary elections were held on August 6, 1946.[1]

Republican primary

[edit]

Candidates

[edit]

Results

[edit]
Republican primary results[1]
Party Candidate Votes %
Republican Charles M. Dale (incumbent) 22,917 49.79
Republican Sherman Adams 22,732 49.39
Republican Elmer E. Bussey 375 0.82
Total votes 46,024 100.00

General election

[edit]

Candidates

[edit]
  • Charles M. Dale, Republican
  • F. Clyde Keefe, Democratic

Results

[edit]
1946 New Hampshire gubernatorial election[2]
Party Candidate Votes % ±%
Republican Charles M. Dale (incumbent) 103,204 63.14%
Democratic F. Clyde Keefe 60,247 36.86%
Majority 42,957
Turnout 163,451
Republican hold Swing

References

[edit]
  1. ^ a b Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved June 1, 2020.
  2. ^ Cook, Rhodes (November 5, 2013). America Votes 30: 2011-2012, Election Returns by State. ISBN 9781452290171. Retrieved June 1, 2020.